MCQ
24161. When the length of a chain along a slope of 0 is L, the correction for slope required is-
I sin²θ/2
I cos²θ/2
2I sin²θ/2
2I cos²θ/2
24162. The tension, at which the effects of pull and sag for a tape are neutralized, is known as-
initial tension
absolute tension
surface tension
normal tension
24163. If the fore bearing of a line is its back bearing will be
36°15′.
126°15′
143°45′
216°15′
24164. If the fore bearing of a line is 36°15′, its back bearing will be-
36°15′
126°15′
143°45′
216°15′
24165. The angle between the reflecting surfaces of a prism square is-
30°
45°
60°
75°
24166. Cumulative errors that occur in chaining are proportional to-
L
√L
1/L
1/√L
24167. An average length of a pace is-
60cm
80cm
100cm
120cm
24168. A line joining the apex of a triangle to some fixed points on the opposite side is called a-
30°
40°
50°
60°
24169. In a direct vernier, the smallest division of a vernier is - the smallest division of its primary scale.
equal to
shorter than
longer than
d none of these
24170. The horizontal angle between the true meridian and magnetic meridian is known as-
true bearing
dip
local attraction
magnetic declination
24171. At the equator, the amount of dip is-
0°
45°
60°
90°
24172. The correction to be applied to each 30m chain for a line measured along a slope of 0 is-
30 (1- sine)
30 (1-cose)
30 (1-tane)
30 (1-cote)
24173. An open cross-staff is commonly used for setting out-
short offsets
long offsets
oblique offsets
none of these
24174. In a prismatic compass, the zero of the graduated ring is located at-
north end
east end
south end
west end
24175. The obstacle, which obstructs vision but not chaining, is a-
river
pond
hill
all of these
24176. The angle of intersection of the horizon glass and index glass in an optical square is-
30°
45°
60°
75°
24177. The obstacle, which obstructs chaining but not vision, is a-
river
pond
hill
all of these
24178. Compensating errors that occur in chaining are proportional to-
L
√L
1/L
1/√L
24179. A French cross-staff has a magnetic compass at the top.
Right
Wrong
24180. In a whole circle bearing system N25°15′W corresponds to-
115°15′
154°45′
205°15′
334°45′